1. The initial speed of the object in m/sec is?1) The initial speed of the object in m/sec is?

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**Correct answer is option - 4**

**Explanation:**The initial speed of the object at point A is 20m/sec.

2. From A to B, the acceleration of the object in m/sec^{2} is?

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**Correct answer is option - 3**

**Explanation: **In a velocity-time graph, the acceleration is the slope of the graph.

The graph from A to B is a straight line and hence the slope which is (change in ‘y’ value)/ (change in ‘x’ value) = (20 – 20)/ (6 – 0) ==> 0/6 = 0 m/sec^{2}.Therefore the acceleration of the object from point A to B is 0 m/sec^{2}.

3. What is the displacement in ‘meters’ covered by the object from point A to B?

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**Correct answer is option - 2**

**Explanation:**Displacement in a velocity-time graph can be calculated by finding the area in between the graph line and the time-axis.In the graph above, the area covered is in the form of a rectangle.

Therefore displacement covered = area covered from point A to B = 20 * 6 = 120m.

4. From point B to point C, what is the direction of the object? Is the object speeding up or slowing down?

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**Correct answer is option - 5**

**Explanation: **Since the velocity of the object as shown in the graph from point B to point C is still positive, hence the object is moving in the positive direction.

However, as time is passing by, the velocity is decreasing from point B to C, and hence the object is slowing down.

5. What is the acceleration of the object from point B to C?

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**Correct answer is option - 4**

**Explanation: **Acceleration in velocity-time graph = Slope of the line from B to C.

Slope = (change in ‘y’ value)/ (change in ‘x’ value)

This gives: (velocity at C – velocity at B)/ (time at C – time at B)

Therefore, acceleration = (0 – 20)/ (10 – 6) ==> -20/4 = -5m/sec^{2}.

6. The total displacement covered by the object from point A to point C is?

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**Correct answer is option - 4**

**Explanation: **The displacement covered from point A to B is the area covered by the rectangle from point A to B with the time-axis = 20 * 6 = 120m. Area covered from point B to C is in the form of a triangle = 1/2 * base * height ==> 1/2 * 4 * 20 = 40m.

This gives the total displacement from point A to C = 120 + 40 = 160m.

7. The object at point C is?

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**Correct answer is option - 5**

**Explanation: **The graph is touching the X-axis at point C and the ‘y’ value or the ‘speed value’ at point C is 0 m/sec and this implies that the object stops or is at rest.